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131103135313254 = 232133493207750047
BaseRepresentation
bin11101110011110011010011…
…110011110010110101100110
3122012012100002220201110201200
4131303303103303302311212
5114140443210120011004
61142455540544103330
736420613624152126
oct3563632363626546
9565170086643650
10131103135313254
113885658903a4a5
12128547ba904b46
13581cc84aa09b0
1424535d5c12c86
15102546041b239
hex773cd3cf2d66

131103135313254 has 96 divisors (see below), whose sum is σ = 306799535078400. Its totient is φ = 40221782827776.

The previous prime is 131103135313223. The next prime is 131103135313259. The reversal of 131103135313254 is 452313531301131.

131103135313254 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 0 + 313 + 5 + 313 + 25 + 4 = 666.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131103135313259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2619575259 + ... + 2619625305.

It is an arithmetic number, because the mean of its divisors is an integer number (3195828490400).

Almost surely, 2131103135313254 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131103135313254, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153399767539200).

131103135313254 is an abundant number, since it is smaller than the sum of its proper divisors (175696399765146).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131103135313254 is a wasteful number, since it uses less digits than its factorization.

131103135313254 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82494 (or 82491 counting only the distinct ones).

The product of its (nonzero) digits is 48600, while the sum is 36.

Adding to 131103135313254 its reverse (452313531301131), we get a palindrome (583416666614385).

The spelling of 131103135313254 in words is "one hundred thirty-one trillion, one hundred three billion, one hundred thirty-five million, three hundred thirteen thousand, two hundred fifty-four".

Divisors: 1 2 3 6 9 13 18 26 39 78 117 234 349 698 1047 2094 3141 4537 6282 9074 13611 27222 32077 40833 50047 64154 81666 96231 100094 150141 192462 288693 300282 417001 450423 577386 650611 834002 900846 1251003 1301222 1951833 2502006 3753009 3903666 5855499 7506018 11194873 11710998 17466403 22389746 33584619 34932806 52399209 67169238 100753857 104798418 145533349 157197627 201507714 227063239 291066698 314395254 436600047 454126478 681189717 873200094 1309800141 1362379434 1605357619 2043569151 2619600282 3210715238 4087138302 4816072857 9632145714 14448218571 20869649047 28896437142 41739298094 62608947141 125217894282 187826841423 375653682846 560269809031 1120539618062 1680809427093 3361618854186 5042428281279 7283507517403 10084856562558 14567015034806 21850522552209 43701045104418 65551567656627 131103135313254