Base | Representation |
---|---|
bin | 11101110011110011100100… |
… | …010000010001000001111010 |
3 | 122012012100211010212121012221 |
4 | 131303303210100101001322 |
5 | 114140444241232244120 |
6 | 1142500024201354254 |
7 | 36420623514232630 |
oct | 3563634420210172 |
9 | 565170733777187 |
10 | 131103411212410 |
11 | 3885670a85262a |
12 | 1285487719898a |
13 | 581ccc9cb0930 |
14 | 2453620711350 |
15 | 10254797690aa |
hex | 773ce441107a |
131103411212410 has 128 divisors (see below), whose sum is σ = 296267883448320. Its totient is φ = 40667821369344.
The previous prime is 131103411212407. The next prime is 131103411212447. The reversal of 131103411212410 is 14212114301131.
It is a super-2 number, since 2×1311034112124102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3193212 + ... + 16504648.
It is an arithmetic number, because the mean of its divisors is an integer number (2314592839440).
Almost surely, 2131103411212410 is an apocalyptic number.
131103411212410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131103411212410 is an abundant number, since it is smaller than the sum of its proper divisors (165164472235910).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131103411212410 is a wasteful number, since it uses less digits than its factorization.
131103411212410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13311680.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 131103411212410 its reverse (14212114301131), we get a palindrome (145315525513541).
The spelling of 131103411212410 in words is "one hundred thirty-one trillion, one hundred three billion, four hundred eleven million, two hundred twelve thousand, four hundred ten".
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