13110401420245 has 4 divisors (see below), whose sum is σ = 15732481704300. Its totient is φ = 10488321136192.

The previous prime is 13110401420191. The next prime is 13110401420251. The reversal of 13110401420245 is 54202410401131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4225125471121 + 8885275949124 = 2055511^2 + 2980818^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110401420245 - 2¹¹ = 13110401418197 is a prime.

It is a super-2 number, since 2×13110401420245² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311040142020 + ... + 1311040142029.

It is an arithmetic number, because the mean of its divisors is an integer number (3933120426075).

Almost surely, 2^{13110401420245} is an apocalyptic number.

It is an amenable number.

13110401420245 is a deficient number, since it is larger than the sum of its proper divisors (2622080284055).

13110401420245 is an equidigital number, since it uses as much as digits as its factorization.

13110401420245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622080284054.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 13110401420245 its reverse (54202410401131), we get a palindrome (67312811821376).

The spelling of 13110401420245 in words is "thirteen trillion, one hundred ten billion, four hundred one million, four hundred twenty thousand, two hundred forty-five".