13110403502034 has 96 divisors (see below), whose sum is σ = 30893001323184. Its totient is φ = 4001989570560.

The previous prime is 13110403501997. The next prime is 13110403502081. The reversal of 13110403502034 is 43020530401131.

It is a happy number.

13110403502034 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 0 + 403 + 50 + 203 + 4 = 666.

It can be written as a sum of positive squares in 8 ways, for example, as 1815742775025 + 11294660727009 = 1347495^2 + 3360753^2 .

It is a super-2 number, since 2×13110403502034² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110403501989 and 13110403502007.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3278872 + ... + 6080444.

Almost surely, 2^{13110403502034} is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110403502034, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15446500661592).

13110403502034 is an abundant number, since it is smaller than the sum of its proper divisors (17782597821150).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110403502034 is a wasteful number, since it uses less digits than its factorization.

13110403502034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2802012 (or 2802009 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 13110403502034 its reverse (43020530401131), we get a palindrome (56130933903165).

The spelling of 13110403502034 in words is "thirteen trillion, one hundred ten billion, four hundred three million, five hundred two thousand, thirty-four".