13110404020220 has 48 divisors (see below), whose sum is σ = 29650157318208. Its totient is φ = 4840687111680.

The previous prime is 13110404020213. The next prime is 13110404020243. The reversal of 13110404020220 is 2202040401131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13110404020192 and 13110404020201.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17383817 + ... + 18122303.

It is an arithmetic number, because the mean of its divisors is an integer number (617711610796).

Almost surely, 2^{13110404020220} is an apocalyptic number.

13110404020220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13110404020220 is an abundant number, since it is smaller than the sum of its proper divisors (16539753297988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110404020220 is a wasteful number, since it uses less digits than its factorization.

13110404020220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 806790 (or 806788 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 13110404020220 its reverse (2202040401131), we get a palindrome (15312444421351).

The spelling of 13110404020220 in words is "thirteen trillion, one hundred ten billion, four hundred four million, twenty thousand, two hundred twenty".