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13110443241134 = 26555221620567
BaseRepresentation
bin1011111011001000001101…
…0011111110111010101110
31201102100100022221111011212
42332302003103332322232
53204300141432204014
643514504322314422
72522125001561141
oct276620323767256
951370308844155
1013110443241134
1141a512046a498
121578a84ab8a12
13741403c56785
14334798028058
1517b07563523e
hexbec834feeae

13110443241134 has 4 divisors (see below), whose sum is σ = 19665664861704. Its totient is φ = 6555221620566.

The previous prime is 13110443241131. The next prime is 13110443241143. The reversal of 13110443241134 is 43114234401131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13110443241134.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110443241131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277610810282 + ... + 3277610810285.

It is an arithmetic number, because the mean of its divisors is an integer number (4916416215426).

Almost surely, 213110443241134 is an apocalyptic number.

13110443241134 is a deficient number, since it is larger than the sum of its proper divisors (6555221620570).

13110443241134 is an equidigital number, since it uses as much as digits as its factorization.

13110443241134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6555221620569.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 13110443241134 its reverse (43114234401131), we get a palindrome (56224677642265).

The spelling of 13110443241134 in words is "thirteen trillion, one hundred ten billion, four hundred forty-three million, two hundred forty-one thousand, one hundred thirty-four".

Divisors: 1 2 6555221620567 13110443241134