Base | Representation |
---|---|
bin | 1011111011001000001101… |
… | …0011111110111010101110 |
3 | 1201102100100022221111011212 |
4 | 2332302003103332322232 |
5 | 3204300141432204014 |
6 | 43514504322314422 |
7 | 2522125001561141 |
oct | 276620323767256 |
9 | 51370308844155 |
10 | 13110443241134 |
11 | 41a512046a498 |
12 | 1578a84ab8a12 |
13 | 741403c56785 |
14 | 334798028058 |
15 | 17b07563523e |
hex | bec834feeae |
13110443241134 has 4 divisors (see below), whose sum is σ = 19665664861704. Its totient is φ = 6555221620566.
The previous prime is 13110443241131. The next prime is 13110443241143. The reversal of 13110443241134 is 43114234401131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13110443241134.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110443241131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277610810282 + ... + 3277610810285.
It is an arithmetic number, because the mean of its divisors is an integer number (4916416215426).
Almost surely, 213110443241134 is an apocalyptic number.
13110443241134 is a deficient number, since it is larger than the sum of its proper divisors (6555221620570).
13110443241134 is an equidigital number, since it uses as much as digits as its factorization.
13110443241134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6555221620569.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 13110443241134 its reverse (43114234401131), we get a palindrome (56224677642265).
The spelling of 13110443241134 in words is "thirteen trillion, one hundred ten billion, four hundred forty-three million, two hundred forty-one thousand, one hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •