Base | Representation |
---|---|
bin | 1011111011001000001101… |
… | …0011111110111010101111 |
3 | 1201102100100022221111011220 |
4 | 2332302003103332322233 |
5 | 3204300141432204020 |
6 | 43514504322314423 |
7 | 2522125001561142 |
oct | 276620323767257 |
9 | 51370308844156 |
10 | 13110443241135 |
11 | 41a512046a499 |
12 | 1578a84ab8a13 |
13 | 741403c56786 |
14 | 334798028059 |
15 | 17b075635240 |
hex | bec834feeaf |
13110443241135 has 32 divisors (see below), whose sum is σ = 21329235651072. Its totient is φ = 6874820542080.
The previous prime is 13110443241131. The next prime is 13110443241143. The reversal of 13110443241135 is 53114234401131.
It is a happy number.
It is not a de Polignac number, because 13110443241135 - 22 = 13110443241131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13110443241096 and 13110443241105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110443241131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 646699 + ... + 5161308.
It is an arithmetic number, because the mean of its divisors is an integer number (666538614096).
Almost surely, 213110443241135 is an apocalyptic number.
13110443241135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13110443241135 is a deficient number, since it is larger than the sum of its proper divisors (8218792409937).
13110443241135 is a wasteful number, since it uses less digits than its factorization.
13110443241135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5810543.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 13110443241135 its reverse (53114234401131), we get a palindrome (66224677642266).
The spelling of 13110443241135 in words is "thirteen trillion, one hundred ten billion, four hundred forty-three million, two hundred forty-one thousand, one hundred thirty-five".
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