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1311055305340 = 22511233735031381
BaseRepresentation
bin10011000101000000111…
…111000101101001111100
311122100001200212011010111
4103011000333011221330
5132440020124232330
62442142425115404
7163502113136314
oct23050077055174
94570050764114
101311055305340
114660195a4780
12192111928b64
139682a616c31
1447653934444
152418478b32a
hex13140fc5a7c

1311055305340 has 192 divisors, whose sum is σ = 3151025805312. Its totient is φ = 453563827200.

The previous prime is 1311055305319. The next prime is 1311055305359. The reversal of 1311055305340 is 435035501131.

It is a super-3 number, since 3×13110553053403 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 949351450 + ... + 949352830.

It is an arithmetic number, because the mean of its divisors is an integer number (16411592736).

Almost surely, 21311055305340 is an apocalyptic number.

1311055305340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311055305340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1575512902656).

1311055305340 is an abundant number, since it is smaller than the sum of its proper divisors (1839970499972).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311055305340 is a wasteful number, since it uses less digits than its factorization.

1311055305340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2300 (or 2298 counting only the distinct ones).

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 1311055305340 in words is "one trillion, three hundred eleven billion, fifty-five million, three hundred five thousand, three hundred forty".