1311102413 has 4 divisors (see below), whose sum is σ = 1311177600. Its totient is φ = 1311027228.

The previous prime is 1311102389. The next prime is 1311102427. The reversal of 1311102413 is 3142011131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3142011131 = 7 ⋅448858733.

It is a cyclic number.

It is not a de Polignac number, because 1311102413 - 2¹² = 1311098317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311102391 and 1311102400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311102433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3638 + ... + 51336.

It is an arithmetic number, because the mean of its divisors is an integer number (327794400).

Almost surely, 2^1311102413 is an apocalyptic number.

It is an amenable number.

1311102413 is a deficient number, since it is larger than the sum of its proper divisors (75187).

1311102413 is an equidigital number, since it uses as much as digits as its factorization.

1311102413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75186.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1311102413 is about 36209.1481948968. The cubic root of 1311102413 is about 1094.4910273325.

Adding to 1311102413 its reverse (3142011131), we get a palindrome (4453113544).

The spelling of 1311102413 in words is "one billion, three hundred eleven million, one hundred two thousand, four hundred thirteen".