Base | Representation |
---|---|
bin | 1011111011001011000100… |
… | …1001101110001111001111 |
3 | 1201102102022221001220011012 |
4 | 2332302301021232033033 |
5 | 3204303230322201221 |
6 | 43515112514115435 |
7 | 2522153030522003 |
oct | 276626111561717 |
9 | 51372287056135 |
10 | 13111212303311 |
11 | 41a548559a271 |
12 | 157905a57bb7b |
13 | 7414c7396855 |
14 | 33482c21c703 |
15 | 17b0bcdea65b |
hex | becb126e3cf |
13111212303311 has 2 divisors, whose sum is σ = 13111212303312. Its totient is φ = 13111212303310.
The previous prime is 13111212303281. The next prime is 13111212303313. The reversal of 13111212303311 is 11330321211131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111212303311 - 218 = 13111212041167 is a prime.
Together with 13111212303313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111212303313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555606151655 + 6555606151656.
It is an arithmetic number, because the mean of its divisors is an integer number (6555606151656).
Almost surely, 213111212303311 is an apocalyptic number.
13111212303311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111212303311 is an equidigital number, since it uses as much as digits as its factorization.
13111212303311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 13111212303311 its reverse (11330321211131), we get a palindrome (24441533514442).
The spelling of 13111212303311 in words is "thirteen trillion, one hundred eleven billion, two hundred twelve million, three hundred three thousand, three hundred eleven".
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