Base | Representation |
---|---|
bin | 10011000101000101101… |
… | …011010010011111100000 |
3 | 11122100021011221022110000 |
4 | 103011011223102133200 |
5 | 132440200301013440 |
6 | 2442154315540000 |
7 | 163504060061136 |
oct | 23050553223740 |
9 | 4570234838400 |
10 | 1311134001120 |
11 | 466059a65009 |
12 | 19213415a600 |
13 | 96840a0b798 |
14 | 4766017b756 |
15 | 2418b633730 |
hex | 13145ad27e0 |
1311134001120 has 240 divisors, whose sum is σ = 4786770764160. Its totient is φ = 337579232256.
The previous prime is 1311134001119. The next prime is 1311134001127. The reversal of 1311134001120 is 211004311131.
It is a happy number.
1311134001120 is a `hidden beast` number, since 1 + 31 + 113 + 400 + 1 + 120 = 666.
It is a tau number, because it is divible by the number of its divisors (240).
It is a super-2 number, since 2×13111340011202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 1311134001093 and 1311134001102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311134001127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1368432 + ... + 2120111.
It is an arithmetic number, because the mean of its divisors is an integer number (19944878184).
Almost surely, 21311134001120 is an apocalyptic number.
1311134001120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311134001120 is an abundant number, since it is smaller than the sum of its proper divisors (3475636763040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311134001120 is a wasteful number, since it uses less digits than its factorization.
1311134001120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3488599 (or 3488582 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1311134001120 its reverse (211004311131), we get a palindrome (1522138312251).
The spelling of 1311134001120 in words is "one trillion, three hundred eleven billion, one hundred thirty-four million, one thousand, one hundred twenty".
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