Base | Representation |
---|---|
bin | 11101110011111110100101… |
… | …000001111110010101011100 |
3 | 122012020111100012011201112110 |
4 | 131303332211001332111130 |
5 | 114141143000230344400 |
6 | 1142505301351034020 |
7 | 36421522522214034 |
oct | 3563764501762534 |
9 | 565214305151473 |
10 | 131115235403100 |
11 | 38860728244053 |
12 | 1285701706b910 |
13 | 58211628aab80 |
14 | 2454022c468c4 |
15 | 102591c85ce50 |
hex | 773fa507e55c |
131115235403100 has 288 divisors, whose sum is σ = 422724560771520. Its totient is φ = 31154578882560.
The previous prime is 131115235403069. The next prime is 131115235403149. The reversal of 131115235403100 is 1304532511131.
It is a super-2 number, since 2×1311152354031002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 510291862 + ... + 510548738.
It is an arithmetic number, because the mean of its divisors is an integer number (1467793613790).
Almost surely, 2131115235403100 is an apocalyptic number.
131115235403100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131115235403100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (211362280385760).
131115235403100 is an abundant number, since it is smaller than the sum of its proper divisors (291609325368420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131115235403100 is a wasteful number, since it uses less digits than its factorization.
131115235403100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 261449 (or 261442 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 131115235403100 its reverse (1304532511131), we get a palindrome (132419767914231).
The spelling of 131115235403100 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred thirty-five million, four hundred three thousand, one hundred".
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