Base | Representation |
---|---|
bin | 1011111011001101001101… |
… | …1101111000011001010100 |
3 | 1201102110211001100222120110 |
4 | 2332303103131320121110 |
5 | 3204310420212410030 |
6 | 43515250001403020 |
7 | 2522203221133215 |
oct | 276632335703124 |
9 | 51373731328513 |
10 | 13111788013140 |
11 | 41a5750567613 |
12 | 157919b339470 |
13 | 74158973935b |
14 | 33488488140c |
15 | 17b10371b1b0 |
hex | becd3778654 |
13111788013140 has 48 divisors (see below), whose sum is σ = 36763505880192. Its totient is φ = 3491667332736.
The previous prime is 13111788013067. The next prime is 13111788013141. The reversal of 13111788013140 is 4131088711131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111788013141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 150251979 + ... + 150339218.
It is an arithmetic number, because the mean of its divisors is an integer number (765906372504).
Almost surely, 213111788013140 is an apocalyptic number.
13111788013140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13111788013140 is an abundant number, since it is smaller than the sum of its proper divisors (23651717867052).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111788013140 is a wasteful number, since it uses less digits than its factorization.
13111788013140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300591936 (or 300591934 counting only the distinct ones).
The product of its (nonzero) digits is 16128, while the sum is 39.
The spelling of 13111788013140 in words is "thirteen trillion, one hundred eleven billion, seven hundred eighty-eight million, thirteen thousand, one hundred forty".
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