131120310432040 has 16 divisors (see below), whose sum is σ = 295020698472180. Its totient is φ = 52448124172800.

The previous prime is 131120310432011. The next prime is 131120310432047. The reversal of 131120310432040 is 40234013021131.

It can be written as a sum of positive squares in 2 ways, for example, as 130715364018724 + 404946413316 = 11433082^2 + 636354^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131120310431996 and 131120310432014.

It is not an unprimeable number, because it can be changed into a prime (131120310432047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1639003880361 + ... + 1639003880440.

Almost surely, 2^{131120310432040} is an apocalyptic number.

131120310432040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131120310432040 is an abundant number, since it is smaller than the sum of its proper divisors (163900388040140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131120310432040 is a wasteful number, since it uses less digits than its factorization.

131120310432040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3278007760812 (or 3278007760808 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131120310432040 its reverse (40234013021131), we get a palindrome (171354323453171).

The spelling of 131120310432040 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred ten million, four hundred thirty-two thousand, forty".