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13112121132000 = 2533531129380591
BaseRepresentation
bin1011111011001110011101…
…0100101000001111100000
31201102111200021012011202000
42332303213110220033200
53204312111002211000
643515343021324000
72522214404451222
oct276634724501740
951374607164660
1013112121132000
1141a5901601760
121579272a06600
137416107618c7
143348b6bd6412
1517b122abd000
hexbece75283e0

13112121132000 has 768 divisors, whose sum is σ = 53862597734400. Its totient is φ = 3069077760000.

The previous prime is 13112121131981. The next prime is 13112121132001. The reversal of 13112121132000 is 23112121131.

13112121132000 is a `hidden beast` number, since 1 + 311 + 21 + 2 + 11 + 320 + 0 + 0 = 666.

It is a super-2 number, since 2×131121211320002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112121132001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 34261705 + ... + 34642295.

It is an arithmetic number, because the mean of its divisors is an integer number (70133590800).

Almost surely, 213112121132000 is an apocalyptic number.

13112121132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112121132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26931298867200).

13112121132000 is an abundant number, since it is smaller than the sum of its proper divisors (40750476602400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112121132000 is a wasteful number, since it uses less digits than its factorization.

13112121132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380665 (or 380641 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13112121132000 its reverse (23112121131), we get a palindrome (13135233253131).

The spelling of 13112121132000 in words is "thirteen trillion, one hundred twelve billion, one hundred twenty-one million, one hundred thirty-two thousand".