131123204401240 has 64 divisors (see below), whose sum is σ = 295142160844800. Its totient is φ = 52428850088832.

The previous prime is 131123204401213. The next prime is 131123204401243. The reversal of 131123204401240 is 42104402321131.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 131123204401199 and 131123204401208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131123204401243) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1132041969 + ... + 1132157791.

It is an arithmetic number, because the mean of its divisors is an integer number (4611596263200).

Almost surely, 2^{131123204401240} is an apocalyptic number.

131123204401240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131123204401240 is an abundant number, since it is smaller than the sum of its proper divisors (164018956443560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131123204401240 is a wasteful number, since it uses less digits than its factorization.

131123204401240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126616 (or 126612 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 131123204401240 its reverse (42104402321131), we get a palindrome (173227606722371).

The spelling of 131123204401240 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, two hundred four million, four hundred one thousand, two hundred forty".