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13113024000 = 29353163419
BaseRepresentation
bin11000011011001100…
…01101111000000000
31020211212110122020120
430031212031320000
5203323413232000
610005105340240
7642644602446
oct141546157000
936755418216
1013113024000
115619a6201a
12265b637680
13130c9255cb
148c578ab96
1551b32a6a0
hex30d98de00

13113024000 has 320 divisors, whose sum is σ = 43969685760. Its totient is φ = 3467059200.

The previous prime is 13113023993. The next prime is 13113024013. The reversal of 13113024000 is 42031131.

It is a tau number, because it is divible by the number of its divisors (320).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31295791 + ... + 31296209.

It is an arithmetic number, because the mean of its divisors is an integer number (137405268).

Almost surely, 213113024000 is an apocalyptic number.

13113024000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113024000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21984842880).

13113024000 is an abundant number, since it is smaller than the sum of its proper divisors (30856661760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113024000 is an equidigital number, since it uses as much as digits as its factorization.

13113024000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 618 (or 592 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13113024000 its reverse (42031131), we get a palindrome (13155055131).

The spelling of 13113024000 in words is "thirteen billion, one hundred thirteen million, twenty-four thousand".