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13113052535 = 511240195393
BaseRepresentation
bin11000011011001100…
…10100110101110111
31020211212112002101102
430031212110311313
5203323420140120
610005110120315
7642645051602
oct141546246567
936755462342
1013113052535
115619a81500
12265b65009b
13130c9355ab
148c5797339
1551b333d75
hex30d994d77

13113052535 has 24 divisors (see below), whose sum is σ = 17303736240. Its totient is φ = 9532624640.

The previous prime is 13113052531. The next prime is 13113052543. The reversal of 13113052535 is 53525031131.

It is a happy number.

It is not a de Polignac number, because 13113052535 - 22 = 13113052531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113052498 and 13113052507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113052531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2428799 + ... + 2434191.

It is an arithmetic number, because the mean of its divisors is an integer number (720989010).

Almost surely, 213113052535 is an apocalyptic number.

13113052535 is a deficient number, since it is larger than the sum of its proper divisors (4190683705).

13113052535 is a wasteful number, since it uses less digits than its factorization.

13113052535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9439 (or 9428 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 29.

Adding to 13113052535 its reverse (53525031131), we get a palindrome (66638083666).

The spelling of 13113052535 in words is "thirteen billion, one hundred thirteen million, fifty-two thousand, five hundred thirty-five".

Divisors: 1 5 11 55 121 605 4019 5393 20095 26965 44209 59323 221045 296615 486299 652553 2431495 3262765 21674467 108372335 238419137 1192095685 2622610507 13113052535