Base | Representation |
---|---|
bin | 10011000101010000110… |
… | …001010111100110110110 |
3 | 11122100202011012100220020 |
4 | 103011100301113212312 |
5 | 132441040424104220 |
6 | 2442225005350010 |
7 | 163511510213511 |
oct | 23052061274666 |
9 | 4570664170806 |
10 | 1311320144310 |
11 | 466145043160 |
12 | 192186568306 |
13 | 96870453897 |
14 | 4767ab93d78 |
15 | 2419cb52040 |
hex | 13150c579b6 |
1311320144310 has 64 divisors (see below), whose sum is σ = 3433405397760. Its totient is φ = 317883678080.
The previous prime is 1311320144279. The next prime is 1311320144317. The reversal of 1311320144310 is 134410231131.
It is a happy number.
It is a super-2 number, since 2×13113201443102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311320144317) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11086261 + ... + 11203919.
It is an arithmetic number, because the mean of its divisors is an integer number (53646959340).
Almost surely, 21311320144310 is an apocalyptic number.
1311320144310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1311320144310 is an abundant number, since it is smaller than the sum of its proper divisors (2122085253450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311320144310 is a wasteful number, since it uses less digits than its factorization.
1311320144310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151453.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 1311320144310 its reverse (134410231131), we get a palindrome (1445730375441).
The spelling of 1311320144310 in words is "one trillion, three hundred eleven billion, three hundred twenty million, one hundred forty-four thousand, three hundred ten".
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