Base | Representation |
---|---|
bin | 100111000101001… |
… | …0111101100001111 |
3 | 10101101112001010022 |
4 | 1032022113230033 |
5 | 10141200410302 |
6 | 334042332355 |
7 | 44332134362 |
oct | 11612275417 |
9 | 3341461108 |
10 | 1311341327 |
11 | 61324416a |
12 | 3071ba0bb |
13 | 17b8a921a |
14 | c62340d9 |
15 | 7a1d08a2 |
hex | 4e297b0f |
1311341327 has 2 divisors, whose sum is σ = 1311341328. Its totient is φ = 1311341326.
The previous prime is 1311341293. The next prime is 1311341329. The reversal of 1311341327 is 7231431131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311341327 - 28 = 1311341071 is a prime.
Together with 1311341329, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311341296 and 1311341305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311341329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655670663 + 655670664.
It is an arithmetic number, because the mean of its divisors is an integer number (655670664).
Almost surely, 21311341327 is an apocalyptic number.
1311341327 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311341327 is an equidigital number, since it uses as much as digits as its factorization.
1311341327 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1512, while the sum is 26.
The square root of 1311341327 is about 36212.4471280249. The cubic root of 1311341327 is about 1094.5575040484.
Adding to 1311341327 its reverse (7231431131), we get a palindrome (8542772458).
The spelling of 1311341327 in words is "one billion, three hundred eleven million, three hundred forty-one thousand, three hundred twenty-seven".
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