13113431130 has 16 divisors (see below), whose sum is σ = 31472234784. Its totient is φ = 3496914960.

The previous prime is 13113431129. The next prime is 13113431143. The reversal of 13113431130 is 3113431131.

13113431130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13113431097 and 13113431106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218557156 + ... + 218557215.

It is an arithmetic number, because the mean of its divisors is an integer number (1967014674).

Almost surely, 2^13113431130 is an apocalyptic number.

13113431130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13113431130 is an abundant number, since it is smaller than the sum of its proper divisors (18358803654).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113431130 is a wasteful number, since it uses less digits than its factorization.

13113431130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437114381.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 13113431130 its reverse (3113431131), we get a palindrome (16226862261).

Subtracting from 13113431130 its reverse (3113431131), we obtain a palindrome (9999999999).

The spelling of 13113431130 in words is "thirteen billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred thirty".