13113433100 has 36 divisors (see below), whose sum is σ = 28580462400. Its totient is φ = 5222458560.

The previous prime is 13113433097. The next prime is 13113433103. The reversal of 13113433100 is 133431131.

It is an interprime number because it is at equal distance from previous prime (13113433097) and next prime (13113433103).

It is a super-2 number, since 2×13113433100² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (13113433103) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 263420 + ... + 309219.

Almost surely, 2^13113433100 is an apocalyptic number.

13113433100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13113433100 is an abundant number, since it is smaller than the sum of its proper divisors (15467029300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113433100 is a wasteful number, since it uses less digits than its factorization.

13113433100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 572882 (or 572875 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13113433100 its reverse (133431131), we get a palindrome (13246864231).

The spelling of 13113433100 in words is "thirteen billion, one hundred thirteen million, four hundred thirty-three thousand, one hundred".