131141111231440 has 20 divisors (see below), whose sum is σ = 304903083613284. Its totient is φ = 52456444492544.

The previous prime is 131141111231423. The next prime is 131141111231497. The reversal of 131141111231440 is 44132111141131.

It can be written as a sum of positive squares in 2 ways, for example, as 53259286026816 + 77881825204624 = 7297896^2 + 8825068^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a junction number, because it is equal to n+sod(n) for n = 131141111231399 and 131141111231408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 819631945117 + ... + 819631945276.

Almost surely, 2^{131141111231440} is an apocalyptic number.

131141111231440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141111231440 is an abundant number, since it is smaller than the sum of its proper divisors (173761972381844).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141111231440 is a wasteful number, since it uses less digits than its factorization.

131141111231440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1639263890406 (or 1639263890400 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 28.

Adding to 131141111231440 its reverse (44132111141131), we get a palindrome (175273222372571).

The spelling of 131141111231440 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred thirty-one thousand, four hundred forty".