Base | Representation |
---|---|
bin | 10011000101010110001… |
… | …101101001000110110100 |
3 | 11122100222111222202220212 |
4 | 103011112031221012310 |
5 | 132441232312121400 |
6 | 2442242030244552 |
7 | 163513666223024 |
oct | 23052615510664 |
9 | 4570874882825 |
10 | 1311411442100 |
11 | 466191630581 |
12 | 1921b1056758 |
13 | 9688633b446 |
14 | 47688d5ba84 |
15 | 241a5b88335 |
hex | 131563691b4 |
1311411442100 has 36 divisors (see below), whose sum is σ = 2846817792000. Its totient is φ = 524370113760.
The previous prime is 1311411442097. The next prime is 1311411442109. The reversal of 1311411442100 is 12441141131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311411442109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2159540 + ... + 2699339.
It is an arithmetic number, because the mean of its divisors is an integer number (79078272000).
Almost surely, 21311411442100 is an apocalyptic number.
1311411442100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311411442100 is an abundant number, since it is smaller than the sum of its proper divisors (1535406349900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311411442100 is a wasteful number, since it uses less digits than its factorization.
1311411442100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4861592 (or 4861585 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1311411442100 its reverse (12441141131), we get a palindrome (1323852583231).
The spelling of 1311411442100 in words is "one trillion, three hundred eleven billion, four hundred eleven million, four hundred forty-two thousand, one hundred".
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