Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0011100100011111010000 |
3 | 1201102200212112222120200221 |
4 | 2332311133103210133100 |
5 | 3204330221313323100 |
6 | 43520314450522424 |
7 | 2522315316540115 |
oct | 276653723443720 |
9 | 51380775876627 |
10 | 13114134120400 |
11 | 41a674490a735 |
12 | 1579734b96414 |
13 | 741871805ac1 |
14 | 334a282b290c |
15 | 17b1de69901a |
hex | bed5f4e47d0 |
13114134120400 has 60 divisors (see below), whose sum is σ = 31515684312544. Its totient is φ = 5244159024000.
The previous prime is 13114134120391. The next prime is 13114134120407. The reversal of 13114134120400 is 402143141131.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114134120407) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3264546 + ... + 6073345.
Almost surely, 213114134120400 is an apocalyptic number.
13114134120400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13114134120400 is an abundant number, since it is smaller than the sum of its proper divisors (18401550192144).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13114134120400 is a wasteful number, since it uses less digits than its factorization.
13114134120400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9341420 (or 9341409 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13114134120400 its reverse (402143141131), we get a palindrome (13516277261531).
The spelling of 13114134120400 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, one hundred twenty thousand, four hundred".
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