Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …000000001010111011000 |
3 | 11122101000021220012011120 |
4 | 103011112320001113120 |
5 | 132441243133122022 |
6 | 2442243104325240 |
7 | 163514162523003 |
oct | 23052670012730 |
9 | 4571007805146 |
10 | 1311422551512 |
11 | 466197929207 |
12 | 1921b4913820 |
13 | 9688872ac68 |
14 | 4768a61053a |
15 | 241a6b2ed5c |
hex | 13156e015d8 |
1311422551512 has 16 divisors (see below), whose sum is σ = 3278556378840. Its totient is φ = 437140850496.
The previous prime is 1311422551511. The next prime is 1311422551519. The reversal of 1311422551512 is 2151552241131.
It is a super-3 number, since 3×13114225515123 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311422551511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27321303133 + ... + 27321303180.
Almost surely, 21311422551512 is an apocalyptic number.
1311422551512 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1311422551512 is an abundant number, since it is smaller than the sum of its proper divisors (1967133827328).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311422551512 is a wasteful number, since it uses less digits than its factorization.
1311422551512 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54642606322 (or 54642606318 counting only the distinct ones).
The product of its digits is 12000, while the sum is 33.
Adding to 1311422551512 its reverse (2151552241131), we get a palindrome (3462974792643).
The spelling of 1311422551512 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred fifty-one thousand, five hundred twelve".
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