Base | Representation |
---|---|
bin | 10011000101100000101… |
… | …011011010000110010000 |
3 | 11122101102202100220112210 |
4 | 103011200223122012100 |
5 | 132442112234021404 |
6 | 2442311301352120 |
7 | 163521230461350 |
oct | 23054053320620 |
9 | 4571382326483 |
10 | 1311587017104 |
11 | 466271750691 |
12 | 19223ba08640 |
13 | 968b3823190 |
14 | 476a43c2b60 |
15 | 241b62ba689 |
hex | 13160ada190 |
1311587017104 has 160 divisors (see below), whose sum is σ = 4178538112000. Its totient is φ = 345219273216.
The previous prime is 1311587017057. The next prime is 1311587017123. The reversal of 1311587017104 is 4017107851131.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1878759 + ... + 2480505.
It is an arithmetic number, because the mean of its divisors is an integer number (26115863200).
Almost surely, 21311587017104 is an apocalyptic number.
1311587017104 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311587017104, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2089269056000).
1311587017104 is an abundant number, since it is smaller than the sum of its proper divisors (2866951094896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311587017104 is a wasteful number, since it uses less digits than its factorization.
1311587017104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 602277 (or 602271 counting only the distinct ones).
The product of its (nonzero) digits is 23520, while the sum is 39.
The spelling of 1311587017104 in words is "one trillion, three hundred eleven billion, five hundred eighty-seven million, seventeen thousand, one hundred four".
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