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131200101341 is a prime number
BaseRepresentation
bin111101000110000100…
…0101010101111011101
3110112122120010201011122
41322030020222233131
54122144211220331
6140134505300325
712323155314041
oct1721410525735
9415576121148
10131200101341
1150707045021
12215167946a5
13c4ab70317a
1464c8a24021
15362d3be17b
hex1e8c22abdd

131200101341 has 2 divisors, whose sum is σ = 131200101342. Its totient is φ = 131200101340.

The previous prime is 131200101287. The next prime is 131200101343. The reversal of 131200101341 is 143101002131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131059204441 + 140896900 = 362021^2 + 11870^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131200101341 is a prime.

It is a Sophie Germain prime.

Together with 131200101343, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131200101343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600050670 + 65600050671.

It is an arithmetic number, because the mean of its divisors is an integer number (65600050671).

Almost surely, 2131200101341 is an apocalyptic number.

It is an amenable number.

131200101341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131200101341 is an equidigital number, since it uses as much as digits as its factorization.

131200101341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131200101341 its reverse (143101002131), we get a palindrome (274301103472).

The spelling of 131200101341 in words is "one hundred thirty-one billion, two hundred million, one hundred one thousand, three hundred forty-one".