Base | Representation |
---|---|
bin | 10011000101111001111… |
… | …001011010110010001010 |
3 | 11122102112020111210001122 |
4 | 103011321321122302022 |
5 | 132443444042322310 |
6 | 2442421254115242 |
7 | 163534556005430 |
oct | 23057171326212 |
9 | 4572466453048 |
10 | 1312010120330 |
11 | 466469566378 |
12 | 19233964bb22 |
13 | 96950393510 |
14 | 4770467cd50 |
15 | 241dd4e4555 |
hex | 13179e5ac8a |
1312010120330 has 128 divisors (see below), whose sum is σ = 2935896606720. Its totient is φ = 411060798720.
The previous prime is 1312010120329. The next prime is 1312010120341. The reversal of 1312010120330 is 330210102131.
It is a super-3 number, since 3×13120101203303 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312010120299 and 1312010120308.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 49935857 + ... + 49962123.
It is an arithmetic number, because the mean of its divisors is an integer number (22936692240).
Almost surely, 21312010120330 is an apocalyptic number.
1312010120330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312010120330 is an abundant number, since it is smaller than the sum of its proper divisors (1623886486390).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312010120330 is a wasteful number, since it uses less digits than its factorization.
1312010120330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26844.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1312010120330 its reverse (330210102131), we get a palindrome (1642220222461).
The spelling of 1312010120330 in words is "one trillion, three hundred twelve billion, ten million, one hundred twenty thousand, three hundred thirty".
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