Search a number
-
+
13120401214140 = 22351137722974323
BaseRepresentation
bin1011111011101101010011…
…0110101000101010111100
31201110022001022121221002220
42332323110312220222330
53204431040202323030
643523232404245340
72522626526133333
oct276732466505274
951408038557086
1013120401214140
1141a9370489a50
12157a9a39a0850
1374233001a8ac
1433506076ad1a
1517b459990a10
hexbeed4da8abc

13120401214140 has 192 divisors, whose sum is σ = 41166267932160. Its totient is φ = 3094268636160.

The previous prime is 13120401214111. The next prime is 13120401214157. The reversal of 13120401214140 is 4141210402131.

It is a happy number.

It is a super-2 number, since 2×131204012141402 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13120401214140.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 176495019 + ... + 176569341.

It is an arithmetic number, because the mean of its divisors is an integer number (214407645480).

Almost surely, 213120401214140 is an apocalyptic number.

13120401214140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13120401214140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20583133966080).

13120401214140 is an abundant number, since it is smaller than the sum of its proper divisors (28045866718020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120401214140 is a wasteful number, since it uses less digits than its factorization.

13120401214140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81612 (or 81610 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 13120401214140 its reverse (4141210402131), we get a palindrome (17261611616271).

The spelling of 13120401214140 in words is "thirteen trillion, one hundred twenty billion, four hundred one million, two hundred fourteen thousand, one hundred forty".