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1312100220103 = 4639282841177
BaseRepresentation
bin10011000101111111010…
…001000111110011000111
311122102202112001022201021
4103011333101013303013
5132444140124020403
62442434233212011
7163540031565121
oct23057721076307
94572675038637
101312100220103
114665054056a2
12192363861007
1396965c4b9aa
1447712614211
15241e63908bd
hex1317f447cc7

1312100220103 has 4 divisors (see below), whose sum is σ = 1312383065920. Its totient is φ = 1311817374288.

The previous prime is 1312100220097. The next prime is 1312100220127. The reversal of 1312100220103 is 3010220012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312100220103 - 213 = 1312100211911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312100260103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141415950 + ... + 141425227.

It is an arithmetic number, because the mean of its divisors is an integer number (328095766480).

Almost surely, 21312100220103 is an apocalyptic number.

1312100220103 is a deficient number, since it is larger than the sum of its proper divisors (282845817).

1312100220103 is an equidigital number, since it uses as much as digits as its factorization.

1312100220103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 282845816.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1312100220103 its reverse (3010220012131), we get a palindrome (4322320232234).

The spelling of 1312100220103 in words is "one trillion, three hundred twelve billion, one hundred million, two hundred twenty thousand, one hundred three".

Divisors: 1 4639 282841177 1312100220103