Base | Representation |
---|---|
bin | 10011000110000000000… |
… | …010110000010110000000 |
3 | 11122102210102112100121221 |
4 | 103012000002300112000 |
5 | 132444201441344412 |
6 | 2442435420124424 |
7 | 163540250305336 |
oct | 23060002602600 |
9 | 4572712470557 |
10 | 1312113231232 |
11 | 4665117920a1 |
12 | 192368096714 |
13 | 96968855c9b |
14 | 4771423db56 |
15 | 241e75b0b07 |
hex | 131800b0580 |
1312113231232 has 16 divisors (see below), whose sum is σ = 2613975578100. Its totient is φ = 656056615552.
The previous prime is 1312113231229. The next prime is 1312113231241. The reversal of 1312113231232 is 2321323112131.
It is a tau number, because it is divible by the number of its divisors (16).
It is a super-2 number, since 2×13121132312322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312113231197 and 1312113231206.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5125442182 + ... + 5125442437.
Almost surely, 21312113231232 is an apocalyptic number.
It is an amenable number.
1312113231232 is a deficient number, since it is larger than the sum of its proper divisors (1301862346868).
1312113231232 is an equidigital number, since it uses as much as digits as its factorization.
1312113231232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10250884633 (or 10250884621 counting only the distinct ones).
The product of its digits is 1296, while the sum is 25.
Adding to 1312113231232 its reverse (2321323112131), we get a palindrome (3633436343363).
The spelling of 1312113231232 in words is "one trillion, three hundred twelve billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred thirty-two".
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