Base | Representation |
---|---|
bin | 10011000110000000101… |
… | …000011100101101101100 |
3 | 11122102211010010100220102 |
4 | 103012000220130231230 |
5 | 132444212004043200 |
6 | 2442440412010232 |
7 | 163540430301200 |
oct | 23060050345554 |
9 | 4572733110812 |
10 | 1312123112300 |
11 | 466517320970 |
12 | 19236b460978 |
13 | 9696a905680 |
14 | 47715692b00 |
15 | 241e83b36d5 |
hex | 13180a1cb6c |
1312123112300 has 216 divisors, whose sum is σ = 3891227039280. Its totient is φ = 377513740800.
The previous prime is 1312123112297. The next prime is 1312123112323. The reversal of 1312123112300 is 32113212131.
It is a happy number.
It is a super-2 number, since 2×13121231123002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 235595 + ... + 1636994.
Almost surely, 21312123112300 is an apocalyptic number.
1312123112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1312123112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1945613519640).
1312123112300 is an abundant number, since it is smaller than the sum of its proper divisors (2579103926980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312123112300 is a wasteful number, since it uses less digits than its factorization.
1312123112300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1872641 (or 1872627 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1312123112300 its reverse (32113212131), we get a palindrome (1344236324431).
The spelling of 1312123112300 in words is "one trillion, three hundred twelve billion, one hundred twenty-three million, one hundred twelve thousand, three hundred".
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