Base | Representation |
---|---|
bin | 11101110101100001000111… |
… | …000000000001001001000000 |
3 | 122012121121102100011102121120 |
4 | 131311201013000001021000 |
5 | 114144411133143430100 |
6 | 1143030035423352240 |
7 | 36432256333450656 |
oct | 3565410700011100 |
9 | 565547370142546 |
10 | 131221032014400 |
11 | 388a1588712aa9 |
12 | 12873622152680 |
13 | 582b1232b3813 |
14 | 24591bba90dd6 |
15 | 10285609070a0 |
hex | 775847001240 |
131221032014400 has 84 divisors (see below), whose sum is σ = 430514335882992. Its totient is φ = 34992275202560.
The previous prime is 131221032014389. The next prime is 131221032014411. The reversal of 131221032014400 is 4410230122131.
It is an interprime number because it is at equal distance from previous prime (131221032014389) and next prime (131221032014411).
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13668852702 + ... + 13668862301.
Almost surely, 2131221032014400 is an apocalyptic number.
131221032014400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131221032014400 is an abundant number, since it is smaller than the sum of its proper divisors (299293303868592).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131221032014400 is a wasteful number, since it uses less digits than its factorization.
131221032014400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27337715028 (or 27337715013 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 131221032014400 its reverse (4410230122131), we get a palindrome (135631262136531).
The spelling of 131221032014400 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, thirty-two million, fourteen thousand, four hundred".
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