Base | Representation |
---|---|
bin | 1011111011110011101010… |
… | …1101111001100011000000 |
3 | 1201110110110102101101222111 |
4 | 2332330322231321203000 |
5 | 3204443040202400000 |
6 | 43524114133545104 |
7 | 2523020060232364 |
oct | 276747255714300 |
9 | 51413412341874 |
10 | 13122110200000 |
11 | 41aa06812a35a |
12 | 157b1a01a5194 |
13 | 7425430c2229 |
14 | 3351837112a4 |
15 | 17b509a1bcba |
hex | bef3ab798c0 |
13122110200000 has 84 divisors (see below), whose sum is σ = 32546901646224. Its totient is φ = 5248844000000.
The previous prime is 13122110199977. The next prime is 13122110200039. The reversal of 13122110200000 is 201122131.
It is a super-2 number, since 2×131221102000002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 32605276 + ... + 33005275.
It is an arithmetic number, because the mean of its divisors is an integer number (387463114836).
Almost surely, 213122110200000 is an apocalyptic number.
13122110200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13122110200000 is an abundant number, since it is smaller than the sum of its proper divisors (19424791446224).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122110200000 is an frugal number, since it uses more digits than its factorization.
13122110200000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65610588 (or 65610558 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 13122110200000 its reverse (201122131), we get a palindrome (13122311322131).
The spelling of 13122110200000 in words is "thirteen trillion, one hundred twenty-two billion, one hundred ten million, two hundred thousand".
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