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131231220110 = 2513123122011
BaseRepresentation
bin111101000110111111…
…1011000000110001110
3110112201201200201002122
41322031333120012032
54122230143020420
6140141540252542
712324013652234
oct1721577300616
9415651621078
10131231220110
115072266a011
12215250a1152
13c4b4caa443
1464ccc04954
153630eb9725
hex1e8dfd818e

131231220110 has 8 divisors (see below), whose sum is σ = 236216196216. Its totient is φ = 52492488040.

The previous prime is 131231220101. The next prime is 131231220149. The reversal of 131231220110 is 11022132131.

131231220110 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6561560996 + ... + 6561561015.

It is an arithmetic number, because the mean of its divisors is an integer number (29527024527).

Almost surely, 2131231220110 is an apocalyptic number.

131231220110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131231220110 is a deficient number, since it is larger than the sum of its proper divisors (104984976106).

131231220110 is a wasteful number, since it uses less digits than its factorization.

131231220110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13123122018.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131231220110 its reverse (11022132131), we get a palindrome (142253352241).

The spelling of 131231220110 in words is "one hundred thirty-one billion, two hundred thirty-one million, two hundred twenty thousand, one hundred ten".

Divisors: 1 2 5 10 13123122011 26246244022 65615610055 131231220110