Base | Representation |
---|---|
bin | 111101000111000011… |
… | …1010110110101101111 |
3 | 110112201212121222210011 |
4 | 1322032013112311233 |
5 | 4122231211441421 |
6 | 140142053154051 |
7 | 12324040514326 |
oct | 1721607266557 |
9 | 415655558704 |
10 | 131233312111 |
11 | 50723868840 |
12 | 2152592b927 |
13 | c4b5560705 |
14 | 64cd1cb0bd |
15 | 363127e4e1 |
hex | 1e8e1d6d6f |
131233312111 has 4 divisors (see below), whose sum is σ = 143163613224. Its totient is φ = 119303011000.
The previous prime is 131233312097. The next prime is 131233312121. The reversal of 131233312111 is 111213332131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111213332131 = 11 ⋅10110302921.
It is a cyclic number.
It is not a de Polignac number, because 131233312111 - 217 = 131233181039 is a prime.
It is a Smith number, since the sum of its digits (22) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131233312121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5965150540 + ... + 5965150561.
It is an arithmetic number, because the mean of its divisors is an integer number (35790903306).
Almost surely, 2131233312111 is an apocalyptic number.
131233312111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131233312111 is a deficient number, since it is larger than the sum of its proper divisors (11930301113).
131233312111 is a wasteful number, since it uses less digits than its factorization.
131233312111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11930301112.
The product of its digits is 324, while the sum is 22.
Adding to 131233312111 its reverse (111213332131), we get a palindrome (242446644242).
It can be divided in two parts, 131233 and 312111, that added together give a palindrome (443344).
The spelling of 131233312111 in words is "one hundred thirty-one billion, two hundred thirty-three million, three hundred twelve thousand, one hundred eleven".
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