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13123410001220 = 2252272890618943
BaseRepresentation
bin1011111011111000100000…
…1100001111110101000100
31201110120211000012011001102
42332332020030033311010
53210003220430014340
643524451125115232
72523064222324331
oct276761014176504
951416730164042
1013123410001220
1141aa674901242
12157b4a3558b18
137426bc48a88c
143352681bd988
1517b583bbd215
hexbef8830fd44

13123410001220 has 24 divisors (see below), whose sum is σ = 27680567007744. Its totient is φ = 5226239047136.

The previous prime is 13123410001171. The next prime is 13123410001243. The reversal of 13123410001220 is 2210001432131.

It is a super-3 number, since 3×131234100012203 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13123410001192 and 13123410001201.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1445304932 + ... + 1445314011.

It is an arithmetic number, because the mean of its divisors is an integer number (1153356958656).

Almost surely, 213123410001220 is an apocalyptic number.

13123410001220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13123410001220 is an abundant number, since it is smaller than the sum of its proper divisors (14557157006524).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13123410001220 is a wasteful number, since it uses less digits than its factorization.

13123410001220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2890619179 (or 2890619177 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13123410001220 its reverse (2210001432131), we get a palindrome (15333411433351).

The spelling of 13123410001220 in words is "thirteen trillion, one hundred twenty-three billion, four hundred ten million, one thousand, two hundred twenty".

Divisors: 1 2 4 5 10 20 227 454 908 1135 2270 4540 2890618943 5781237886 11562475772 14453094715 28906189430 57812378860 656170500061 1312341000122 2624682000244 3280852500305 6561705000610 13123410001220