Search a number
-
+
13124201320110 = 235437473377337
BaseRepresentation
bin1011111011111011011101…
…0110111000111010101110
31201110122212011012022111110
42332332313112320322232
53210011331014220420
643525101433532450
72523122641403436
oct276766726707256
951418764168443
1013124201320110
1141aaa405528a1
12157b684574126
137427b73c12ca
143353013292c6
1517b5cd3ccee0
hexbefb75b8eae

13124201320110 has 16 divisors (see below), whose sum is σ = 31498083168336. Its totient is φ = 3499787018688.

The previous prime is 13124201320091. The next prime is 13124201320141. The reversal of 13124201320110 is 1102310242131.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218736688639 + ... + 218736688698.

It is an arithmetic number, because the mean of its divisors is an integer number (1968630198021).

Almost surely, 213124201320110 is an apocalyptic number.

13124201320110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13124201320110 is an abundant number, since it is smaller than the sum of its proper divisors (18373881848226).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13124201320110 is a wasteful number, since it uses less digits than its factorization.

13124201320110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437473377347.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13124201320110 its reverse (1102310242131), we get a palindrome (14226511562241).

The spelling of 13124201320110 in words is "thirteen trillion, one hundred twenty-four billion, two hundred one million, three hundred twenty thousand, one hundred ten".

Divisors: 1 2 3 5 6 10 15 30 437473377337 874946754674 1312420132011 2187366886685 2624840264022 4374733773370 6562100660055 13124201320110