Base | Representation |
---|---|
bin | 111101000111100110… |
… | …0000011001101100010 |
3 | 110112210010111212111001 |
4 | 1322033030003031202 |
5 | 4122300314212100 |
6 | 140143535142214 |
7 | 12324346544413 |
oct | 1721714031542 |
9 | 415703455431 |
10 | 131251319650 |
11 | 50732a48100 |
12 | 2152b97496a |
13 | c4b91c6c69 |
14 | 64d175780a |
15 | 3632b39d6a |
hex | 1e8f303362 |
131251319650 has 36 divisors (see below), whose sum is σ = 268338454146. Its totient is φ = 47727750400.
The previous prime is 131251319593. The next prime is 131251319657. The reversal of 131251319650 is 56913152131.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 53549199649 + 77702120001 = 231407^2 + 278751^2 .
It is a super-2 number, since 2×1312513196502 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131251319657) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 10841167 + ... + 10853266.
Almost surely, 2131251319650 is an apocalyptic number.
131251319650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131251319650 is an abundant number, since it is smaller than the sum of its proper divisors (137087134496).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131251319650 is a wasteful number, since it uses less digits than its factorization.
131251319650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21694467 (or 21694451 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 37.
The spelling of 131251319650 in words is "one hundred thirty-one billion, two hundred fifty-one million, three hundred nineteen thousand, six hundred fifty".
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