Base | Representation |
---|---|
bin | 11000011100101010… |
… | …11101111000011111 |
3 | 1020212201202221002201 |
4 | 30032111131320133 |
5 | 203340101112320 |
6 | 10010231032331 |
7 | 643155101302 |
oct | 141625357037 |
9 | 36781687081 |
10 | 13125410335 |
11 | 5625a52064 |
12 | 266380b6a7 |
13 | 13123713bb |
14 | 8c7292b39 |
15 | 51c47570a |
hex | 30e55de1f |
13125410335 has 4 divisors (see below), whose sum is σ = 15750492408. Its totient is φ = 10500328264.
The previous prime is 13125410329. The next prime is 13125410351. The reversal of 13125410335 is 53301452131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13125410335 - 23 = 13125410327 is a prime.
It is a super-5 number, since 5×131254103355 (a number of 52 digits) contains 55555 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312541029 + ... + 1312541038.
It is an arithmetic number, because the mean of its divisors is an integer number (3937623102).
Almost surely, 213125410335 is an apocalyptic number.
13125410335 is a deficient number, since it is larger than the sum of its proper divisors (2625082073).
13125410335 is an equidigital number, since it uses as much as digits as its factorization.
13125410335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2625082072.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 13125410335 its reverse (53301452131), we get a palindrome (66426862466).
The spelling of 13125410335 in words is "thirteen billion, one hundred twenty-five million, four hundred ten thousand, three hundred thirty-five".
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