Base | Representation |
---|---|
bin | 111101001001000011… |
… | …0111110001101111000 |
3 | 110112220112201100111021 |
4 | 1322102012332031320 |
5 | 4122400340220440 |
6 | 140152445312224 |
7 | 12325513210054 |
oct | 1722206761570 |
9 | 415815640437 |
10 | 131300320120 |
11 | 50758675962 |
12 | 21544265674 |
13 | c4c63c2418 |
14 | 64d8070c64 |
15 | 36370b884a |
hex | 1e921be378 |
131300320120 has 64 divisors (see below), whose sum is σ = 297867572640. Its totient is φ = 52086528000.
The previous prime is 131300320117. The next prime is 131300320127. The reversal of 131300320120 is 21023003131.
It is a super-2 number, since 2×1313003201202 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131300320094 and 131300320103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131300320127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9430284 + ... + 9444196.
Almost surely, 2131300320120 is an apocalyptic number.
131300320120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131300320120 is an abundant number, since it is smaller than the sum of its proper divisors (166567252520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131300320120 is a wasteful number, since it uses less digits than its factorization.
131300320120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15856 (or 15852 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 131300320120 its reverse (21023003131), we get a palindrome (152323323251).
The spelling of 131300320120 in words is "one hundred thirty-one billion, three hundred million, three hundred twenty thousand, one hundred twenty".
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