Base | Representation |
---|---|
bin | 11101110110101101011101… |
… | …111111000010011110001100 |
3 | 122012220110001100210212112110 |
4 | 131312231131333002132030 |
5 | 114202232042113343200 |
6 | 1143131435305504020 |
7 | 36441221201105505 |
oct | 3566553577023614 |
9 | 565813040725473 |
10 | 131303022012300 |
11 | 38923331954a46 |
12 | 128874a44a2010 |
13 | 5835a8b7a0188 |
14 | 245d158c3dbac |
15 | 102a75d95eb50 |
hex | 776b5dfc278c |
131303022012300 has 72 divisors (see below), whose sum is σ = 379904874993616. Its totient is φ = 35014004213760.
The previous prime is 131303022012269. The next prime is 131303022012313. The reversal of 131303022012300 is 3210220303131.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 95350272 + ... + 96717528.
Almost surely, 2131303022012300 is an apocalyptic number.
131303022012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131303022012300 is an abundant number, since it is smaller than the sum of its proper divisors (248601852981316).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131303022012300 is a wasteful number, since it uses less digits than its factorization.
131303022012300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1687387 (or 1687380 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 131303022012300 its reverse (3210220303131), we get a palindrome (134513242315431).
The spelling of 131303022012300 in words is "one hundred thirty-one trillion, three hundred three billion, twenty-two million, twelve thousand, three hundred".
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