Base | Representation |
---|---|
bin | 11101110110110100010101… |
… | …110101001011010110111100 |
3 | 122012221011002122102201120012 |
4 | 131312310111311023112330 |
5 | 114202342200224333200 |
6 | 1143135055435442352 |
7 | 36441602104640201 |
oct | 3566642565132674 |
9 | 565834078381505 |
10 | 131310401402300 |
11 | 3892647937796a |
12 | 12888a038b63b8 |
13 | 583669657c733 |
14 | 245d658d17ca8 |
15 | 102aa4171aa35 |
hex | 776d15d4b5bc |
131310401402300 has 72 divisors (see below), whose sum is σ = 286839474952800. Its totient is φ = 52174706688000.
The previous prime is 131310401402293. The next prime is 131310401402333. The reversal of 131310401402300 is 3204104013131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 568384412 + ... + 568615388.
Almost surely, 2131310401402300 is an apocalyptic number.
131310401402300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131310401402300 is an abundant number, since it is smaller than the sum of its proper divisors (155529073550500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131310401402300 is a wasteful number, since it uses less digits than its factorization.
131310401402300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 268791 (or 268784 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 131310401402300 its reverse (3204104013131), we get a palindrome (134514505415431).
The spelling of 131310401402300 in words is "one hundred thirty-one trillion, three hundred ten billion, four hundred one million, four hundred two thousand, three hundred".
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