13131044013130 has 8 divisors (see below), whose sum is σ = 23635879223652. Its totient is φ = 5252417605248.

The previous prime is 13131044013083. The next prime is 13131044013167. The reversal of 13131044013130 is 3131044013131.

It can be written as a sum of positive squares in 2 ways, for example, as 11580129955681 + 1550914057449 = 3402959^2 + 1245357^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×13131044013130³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13131044013095 and 13131044013104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 656552200647 + ... + 656552200666.

Almost surely, 2^{13131044013130} is an apocalyptic number.

13131044013130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13131044013130 is a deficient number, since it is larger than the sum of its proper divisors (10504835210522).

13131044013130 is a wasteful number, since it uses less digits than its factorization.

13131044013130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1313104401320.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13131044013130 its reverse (3131044013131), we get a palindrome (16262088026261).

Subtracting from 13131044013130 its reverse (3131044013131), we obtain a palindrome (9999999999999).

The spelling of 13131044013130 in words is "thirteen trillion, one hundred thirty-one billion, forty-four million, thirteen thousand, one hundred thirty".