13131044013131 has 16 divisors (see below), whose sum is σ = 14631259281408. Its totient is φ = 11681968492800.

The previous prime is 13131044013083. The next prime is 13131044013167.

13131044013131 is nontrivially palindromic in base 10.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131044013131 is a prime.

It is a super-3 number, since 3×13131044013131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13131044013131.

It is not an unprimeable number, because it can be changed into a prime (13131044513131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2985371 + ... + 5930811.

It is an arithmetic number, because the mean of its divisors is an integer number (914453705088).

Almost surely, 2^{13131044013131} is an apocalyptic number.

13131044013131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13131044013131 is a deficient number, since it is larger than the sum of its proper divisors (1500215268277).

13131044013131 is a wasteful number, since it uses less digits than its factorization.

13131044013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2954122.

The product of its (nonzero) digits is 1296, while the sum is 26.

It can be divided in two parts, 1313104 and 4013131, that added together give a palindrome (5326235).

The spelling of 13131044013131 in words is "thirteen trillion, one hundred thirty-one billion, forty-four million, thirteen thousand, one hundred thirty-one".