13131044013132 has 72 divisors (see below), whose sum is σ = 34111723532432. Its totient is φ = 4255934659200.

The previous prime is 13131044013083. The next prime is 13131044013167. The reversal of 13131044013132 is 23131044013131.

13131044013132 is a `hidden beast` number, since 1 + 31 + 31 + 0 + 440 + 131 + 32 = 666.

It is a super-3 number, since 3×13131044013132³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13131044013096 and 13131044013105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1180219 + ... + 5258802.

Almost surely, 2^{13131044013132} is an apocalyptic number.

13131044013132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13131044013132 is an abundant number, since it is smaller than the sum of its proper divisors (20980679519300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131044013132 is a wasteful number, since it uses less digits than its factorization.

13131044013132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6440599 (or 6440594 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 13131044013132 its reverse (23131044013131), we get a palindrome (36262088026263).

Subtracting 13131044013132 from its reverse (23131044013131), we obtain a palindrome (9999999999999).

The spelling of 13131044013132 in words is "thirteen trillion, one hundred thirty-one billion, forty-four million, thirteen thousand, one hundred thirty-two".