Base | Representation |
---|---|
bin | 1011111100010101001101… |
… | …0100111011111100010000 |
3 | 1201111022200211210002221201 |
4 | 2333011103110323330100 |
5 | 3210120004413134300 |
6 | 43532203335400544 |
7 | 2523456136033456 |
oct | 277052324737420 |
9 | 51438624702851 |
10 | 13131113021200 |
11 | 4202967a78159 |
12 | 1580a93223154 |
13 | 74334931c675 |
14 | 33579925c9d6 |
15 | 17b8850a466a |
hex | bf15353bf10 |
13131113021200 has 60 divisors (see below), whose sum is σ = 31836925735780. Its totient is φ = 5204257620480.
The previous prime is 13131113021113. The next prime is 13131113021219. The reversal of 13131113021200 is 212031113131.
It can be written as a sum of positive squares in 6 ways, for example, as 1351582955776 + 11779530065424 = 1162576^2 + 3432132^2 .
It is a super-2 number, since 2×131311130212002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 150542559 + ... + 150629758.
Almost surely, 213131113021200 is an apocalyptic number.
13131113021200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13131113021200 is an abundant number, since it is smaller than the sum of its proper divisors (18705812714580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13131113021200 is a wasteful number, since it uses less digits than its factorization.
13131113021200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 301172444 (or 301172433 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13131113021200 its reverse (212031113131), we get a palindrome (13343144134331).
The spelling of 13131113021200 in words is "thirteen trillion, one hundred thirty-one billion, one hundred thirteen million, twenty-one thousand, two hundred".
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