Base | Representation |
---|---|
bin | 1011111100010101001111… |
… | …1000010111111111010000 |
3 | 1201111022201111021002022211 |
4 | 2333011103320113333100 |
5 | 3210120014302423440 |
6 | 43532204310441504 |
7 | 2523456311015002 |
oct | 277052370277720 |
9 | 51438644232284 |
10 | 13131122311120 |
11 | 4202972242880 |
12 | 1580a96363294 |
13 | 74334b222c68 |
14 | 33579a59a372 |
15 | 17b885cdbeea |
hex | bf153e17fd0 |
13131122311120 has 160 divisors (see below), whose sum is σ = 33655359669120. Its totient is φ = 4724785643520.
The previous prime is 13131122311103. The next prime is 13131122311169. The reversal of 13131122311120 is 2111322113131.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 13131122311091 and 13131122311100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 539719116 + ... + 539743444.
It is an arithmetic number, because the mean of its divisors is an integer number (210345997932).
Almost surely, 213131122311120 is an apocalyptic number.
13131122311120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13131122311120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16827679834560).
13131122311120 is an abundant number, since it is smaller than the sum of its proper divisors (20524237358000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13131122311120 is a wasteful number, since it uses less digits than its factorization.
13131122311120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30773 (or 30767 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 13131122311120 its reverse (2111322113131), we get a palindrome (15242444424251).
The spelling of 13131122311120 in words is "thirteen trillion, one hundred thirty-one billion, one hundred twenty-two million, three hundred eleven thousand, one hundred twenty".
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