1313133014440 has 64 divisors (see below), whose sum is σ = 3255818227200. Its totient is φ = 473573544192.

The previous prime is 1313133014341. The next prime is 1313133014443. The reversal of 1313133014440 is 444103313131.

It is a super-2 number, since 2×1313133014440² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313133014399 and 1313133014408.

It is not an unprimeable number, because it can be changed into a prime (1313133014443) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29341080 + ... + 29385799.

It is an arithmetic number, because the mean of its divisors is an integer number (50872159800).

Almost surely, 2^{1313133014440} is an apocalyptic number.

1313133014440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1313133014440 is an abundant number, since it is smaller than the sum of its proper divisors (1942685212760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313133014440 is a wasteful number, since it uses less digits than its factorization.

1313133014440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58726946 (or 58726942 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1313133014440 its reverse (444103313131), we get a palindrome (1757236327571).

The spelling of 1313133014440 in words is "one trillion, three hundred thirteen billion, one hundred thirty-three million, fourteen thousand, four hundred forty".